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The Fibonacci Numbers
We define the n-th fibonacci number as follows
  • F0=0 and F1=1
  • Fn=Fn−1+Fn−2 for every n≥2
Sum Equals Jump 2 minus One
For every n∈ℕ0 we have F0+F1+⋯+Fn=Fn+2−1
We prove it by induction, for the base case F(0+2)−1=(F1+F0)−1=1+0−1=0=F0 as needed. Next assume it holds true for k∈ℕ0 and then we want to prove that Fk+3−1=F0+…+Fk+1, we can handle the sum with the inductive hypothesis, so that F0+…+Fk+Fk+1=(Fk+2−1)+Fk+1=Fk+3−1 as needed.