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Partial Summation (or Abel's Summation)
Let {an} be a sequence of complex numbers and f(t) be a continuously differentiable function. Let A(t)=ntan, then nxanf(n)=A(x)f(x)1xA(t)f(x)dt
Use the fact stated below, nxanf(n)=nx(A(n)A(n1))f(n)=nxA(n)f(n)nx1A(n)f(n+1)=nx1A(n)(f(n)f(n+1))+A(x)f(x)=A(x)f(x)+nx1A(n)n+1nf(t)dt=A(x)f(x)+nx1n+1nA(n)f(t)dt=A(x)f(x)1xA(n)f(t)dt

Remark:

  1. Here an is an Arithmetic function
  2. Fact: an=A(n)A(n1)
  3. When x, then A(x)f(x)f(x)xxA(t)f(t)dt=0

More General Version
Let 0λ1<λ2<... be an increasing real sequence and Cn be a complex sequence. Let C(t)=λntCn and f(t) be a continuous derivative, then for xλ1, λnxCnf(λn)=C(x)f(x)λ1xC(t)f(x)dt and if C(x)f(x)0 as x, then n=1Cnf(λn)=λ1C(t)f(t)dt